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The rotation rate of a stator rotating magnetic field is related to
the number of pole pairs per stator phase. The “full speed” Figure
below has a total of six poles or three pole-pairs and three phases.
However, there is but one pole pair per phase-- the number we need. The
magnetic field will rotate once per sine wave cycle. In the case of 60
Hz power, the field rotates at 60 times per second or 3600 revolutions
per minute (rpm). For 50 Hz power, it rotates at 50 rotations per
second, or 3000 rpm. The 3600 and 3000 rpm, are the synchronous speed
of the motor. Though the rotor of an induction motor never achieves this
speed, it certainly is an upper limit. If we double the number of motor
poles, the synchronous speed is cut in half because the magnetic field
rotates 180o in space for 360o of electrical sine
wave.

Doubling the stator poles halves the synchronous speed.
The synchronous speed is given by:
Ns = 120·f/P
Ns = synchronous speed in rpm
f = frequency of applied power, Hz
P = total number of poles per phase, a multiple of 2
Example:
The “half speed” Figure
above has four poles per phase (3-phase). The synchronous speed for
50 Hz power is:
S = 120·50/4 = 1500 rpm
The short explanation of the induction motor is that the rotating
magnetic field produced by the stator drags the rotor around with it.
The longer more correct explanation is that the stator's magnetic
field induces an alternating current into the rotor squirrel cage
conductors which constitutes a transformer secondary. This induced rotor
current in turn creates a magnetic field. The rotating stator magnetic
field interacts with this rotor field. The rotor field attempts to align
with the rotating stator field. The result is rotation of the squirrel
cage rotor. If there were no mechanical motor torque load, no bearing,
windage, or other losses, the rotor would rotate at the synchronous
speed. However, the slip between the rotor and the synchronous
speed stator field develops torque. It is the magnetic flux cutting the
rotor conductors as it slips which develops torque. Thus, a loaded motor
will slip in proportion to the mechanical load. If the rotor were to run
at synchronous speed, there would be no stator flux cutting the rotor,
no current induced in the rotor, no torque.
When power is first applied to the motor, the rotor is at rest, while
the stator magnetic field rotates at the synchronous speed Ns.
The stator field is cutting the rotor at the synchronous speed Ns.
The current induced in the rotor shorted turns is maximum, as is the
frequency of the current, the line frequency. As the rotor speeds up,
the rate at which stator flux cuts the rotor is the difference between
synchronous speed Ns and actual rotor speed N, or (Ns
- N). The ratio of actual flux cutting the rotor to synchronous speed is
defined as slip:
s = (Ns - N)/Ns
where: Ns = synchronous speed, N = rotor speed
The frequency of the current induced into the rotor conductors is
only as high as the line frequency at motor start, decreasing as the
rotor approaches synchronous speed. Rotor frequency is given by:
fr = s·f
where: s = slip, f = stator power line frequency
Slip at 100% torque is typically 5% or less in induction motors. Thus
for f = 50 Hz line frequency, the frequency of the induced current in
the rotor fr = 0.05·50 = 2.5 Hz. Why is it so low? The stator
magnetic field rotates at 50 Hz. The rotor speed is 5% less. The
rotating magnetic field is only cutting the rotor at 2.5 Hz. The 2.5 Hz
is the difference between the synchronous speed and the actual rotor
speed. If the rotor spins a little faster, at the synchronous speed, no
flux will cut the rotor at all, fr = 0.

Torque and speed vs %Slip. %Ns=%Synchronous Speed.
The Figure
above graph shows that starting torque known as locked rotor
torque (LRT) is higher than 100% of the full load torque
(FLT), the safe continuous torque rating. The locked rotor torque is
about 175% of FLT for the example motor graphed above. Starting current
known as locked rotor current (LRC) is 500% of full load
current (FLC), the safe running current. The current is high because
this is analogous to a shorted secondary on a transformer. As the rotor
starts to rotate the torque may decrease a bit for certain classes of
motors to a value known as the pull up torque. This is the lowest
value of torque ever encountered by the starting motor. As the rotor
gains 80% of synchronous speed, torque increases from 175% up to 300% of
the full load torque. This breakdown torque is due to the larger
than normal 20% slip. The current has decreased only slightly at this
point, but will decrease rapidly beyond this point. As the rotor
accelerates to within a few percent of synchronous speed, both torque
and current will decrease substantially. Slip will be only a few percent
during normal operation. For a running motor, any portion of the torque
curve below 100% rated torque is normal. The motor load determines the
operating point on the torque curve. While the motor torque and current
may exceed 100% for a few seconds during starting, continuous operation
above 100% can damage the motor. Any motor torque load above the
breakdown torque will stall the motor. The torque, slip, and current
will approach zero for a “no mechanical torque” load condition. This
condition is analogous to an open secondary transformer.
There are several basic induction motor designs (Figure
below) showing considerable variation from the torque curve above.
The different designs are optimized for starting and running different
types of loads. The locked rotor torque (LRT) for various motor designs
and sizes ranges from 60% to 350% of full load torque (FLT). Starting
current or locked rotor current (LRC) can range from 500% to 1400% of
full load current (FLC). This current draw can present a starting
problem for large induction motors.
Various standard classes (or designs) for motors, corresponding to
the torque curves (Figure
below) have been developed to better drive various type loads. The
National Electrical Manufacturers Association (NEMA) has specified motor
classes A, B, C, and D to meet these drive requirements. Similar
International Electrotechnical Commission (IEC) classes N and H
correspond to NEMA B and C designs respectively.
Characteristics for NEMA designs.
All motors, except class D, operate at %5 slip or less at full load.
- Class B (IEC Class N) motors are the default motor to use
in most applications. With a starting torque of LRT = 150% to 170% of
FLT, it can start most loads, without excessive starting current (LRT).
Efficiency and power factor are high. It typically drives pumps, fans,
and machine tools.
- Class A starting torque is the same as class B. Drop out
torque and starting current (LRT)are higher. This motor handles
transient overloads as encountered in injection molding machines.
- Class C (IEC Class H) has higher starting torque than class
A and B at LRT = 200% of FLT. This motor is applied to hard-starting
loads which need to be driven at constant speed like conveyors,
crushers, and reciprocating pumps and compressors.
- Class D motors have the highest starting torque (LRT)
coupled with low starting current due to high slip ( 5% to 13% at
FLT). The high slip results in lower speed. Speed regulation is poor.
However, the motor excels at driving highly variable speed loads like
those requiring an energy storage flywheel. Applications include punch
presses, shears, and elevators.
- Class E motors are a higher efficiency version of class B.
- Class F motors have much lower LRC, LRT, and break down
torque than class B. They drive constant easily started loads.
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